## ** Nibiru Math Problems **

 ** Nibiru Math Problems ** According to information about Nibiru, Nibiru is 4 times the size of the Earth. Let's assume this means that the Surface Area of Nibiru is 4 times the Surface Area of the Earth. If this is true, what is the Radius of Nibiru? Let A1 = Surface Area of the Earth Let R1 = Radius of the Earth Let A2 = Surface Area of the Nibiru Let R2 = Radius of the Nibiru A1 = (4*R1*R1)*(Pi) A2 = (4*R2*R2)*(Pi) = 4*A1 => A2/A1 = (R2*R2)/(R1*R1) = 4 => R2/R1 = SqRt(4) = 2 => R2 = 2*R1 = 2*3959 = 7918 miles Other information about Nibiru, says Nibiru is 10 times the Mass of the Earth. Let's assume this means that the lbs per CuFt of Nibiru is 10 times the lbs per CuFt of Earth. If this is true, what is the Radius of Nibiru? For this problem we will assume that the average lbs per CuFt of Earth and Nibiru are the same and = 345 lbs per CuFt. Let V1 = CuFt of the Earth Let R1 = Radius of the Earth Let V2 = CuFt of the Nibiru Let R2 = Radius of the Nibiru Let K = CuFt per Cubic Mile = Conversion Factor V1 = (4/3)*(R1*R1*R1)*(Pi)*(K) V2 = (4/3)*(R2*R2*R2)*(Pi)*(K) V2 = 10*V1 => V2/V1 = 10 => (R2*R2*R2)/(R1*R1*R1) = 10 => R2/R1 = CubeRoot(10) = 2.1544 => R2 = 2.1544*R1 = 2.1544*3959 = 8529 miles Radius Percent Difference = 8529 - 7918 = 611 => 611/7918 = .077 => 7.7% => The true Radius must be close to these numbers.! ** Now for the hard problem ** Assuming Nibiru has life similar to life on Earth, and that the Gravity on Nibiru is 1.2 times the Gravity on Earth so that life as we know it would not be overwhelmed by crushing Gravity. Given that R2 = 7918 miles = 2*R1 And that the Gravity on Earth is directly related to the Density of Earth = 345 lbs per CuFt, What should the Density of Nibiru be so that the Gravity there is 1.2 times the Gravity on Earth? Let K = CuFt per Cubic Mile = Conversion Factor Let X = lbs per CuFt for Nibiru V1 = (4/3)*(R1*R1*R1)*(Pi)*(K)*(345)*(1.2) = lbs V2 = (4/3)*(R2*R2*R2)*(Pi)*(K)*(X) = lbs V2/V1 = ((R2*R2*R2)*(X))/((R1*R1*R1)*(345)*(1.2)) = 8 Since R2 = 2*R1 => (R2*R2*R2) = (R1*R1*R1)*8 => X = ((R1*R1*R1)*(345)*(1.2))/(R2*R2*R2) => X = ((R1*R1*R1)*(345)*(1.2))/((R1*R1*R1)*8) => X = (345*1.2)/8 = 51.75 lbs per CuFt = Density of Nibiru